
	Applies To

	Product(s):	AutoPIPE
	Version(s):	ALL
	Area:	Modeling
	Original Author:	Bentley Technical Support Group
	Date Logged & Current Version	Mar. 2015 09.06.01.10

Problem:

How to model a 3 degree mitered joint with 1 cut on the horizontal X-Y plane in AutoPIPE?

Solution:

One method of creating a 3.00 degree mitered joint perform the following Steps:

a. Insert a bend pipe component, choose Bend Type = Close and Wide, cuts = 1, and set Dx=5.00 ft, Dy =0.00, Dz = 0.00

(note: the user is responsible for predetermining whether the miter bend is closely or widely spaced. The current version of AutoPIPE does not trap an incorrectly specified miter bend. see online help for more information on determining the bend type)

b. Insert a straight run of pipe exiting the bend. On the Run dialog, enable check-box labeled "User cylindrical coordinates system", Theta = 3.00 deg, Rad = 5.00 ft and press OK button to insert bend.

Done.

From a a plan view, see that run B06 - B07 is rotated 3.0 deg on the X-Y plane from the B05 - B06 pipe that is on the global X-axis.

Note:

1. if the mitered bend in not facing the correct direction, modify the run end point B07, or select the run and rotate it about the pipe axis (X-axis in this example) to the correct direction.

2. See ASME B31.3 304.2.3 for details about bend angles < 3.0 deg.

13a. How to model a 3 degree mitered joint with 1 cut on the horizontal X-Y plane in AutoPIPE?

Problem:

Solution:

See Also